17x^2+32x-80=0

Solution for 17x^2+32x-80=0 equation:

17x^2+32x-80=0

a = 17; b = 32; c = -80;
Δ = b2-4ac
Δ = 322-4·17·(-80)
Δ = 6464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6464}=\sqrt{64*101}=\sqrt{64}*\sqrt{101}=8\sqrt{101}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8\sqrt{101}}{2*17}=\frac{-32-8\sqrt{101}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8\sqrt{101}}{2*17}=\frac{-32+8\sqrt{101}}{34}
$